document.write( "Question 146717: find the equation of a circle with radius 5 and centered at (3,-1)? thanks!!! \n" ); document.write( "
Algebra.Com's Answer #107143 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Using the equation \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" we can see that \"h=3\", \"k=-1\" and \"r=5\". So the equation is \"%28x-3%29%5E2%2B%28y-%28-1%29%29%5E2=5%5E2\" which simplifies to \"%28x-3%29%5E2%2B%28y%2B1%29%5E2=25\"\r
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\n" ); document.write( "\n" ); document.write( "Now we need to expand and simplify \"%28x-3%29%5E2%2B%28y%2B1%29%5E2=25\" \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2%2B%28y%2B1%29%5E2=25\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2B9%2B%28y%2B1%29%5E2=25\" Foil \"%28x-3%29%5E2\" to get \"x%5E2-6x%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2B9%2By%5E2%2B2y%2B1=25\" Foil \"%28y%2B1%29%5E2\" to get \"y%5E2%2B2y%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2B9%2By%5E2%2B2y%2B1-25=0\" Subtract 25 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2-6x%2B2y-15=0\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So the equation is \"x%5E2%2By%5E2-6x%2B2y-15=0\"
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