document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146666>Question 146666</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534433499/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I would appreciate assistance with this word problem, thanks!<BR>\n" );
document.write( "A chemist has three different acid solutions.  The first acid solution contains 20% acid, the second contains 40%, and the third contains 60%.  He wants to use all three solutions to obtain a mixture of 60 liters containing 50% acid, using twice as much of the 60% solution as the 40% solution.  How many liters of each solution should be used. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107092 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x(60%)+x(40%)+(60-3x)(20%)=60(50%) __ multiplying by 10 __ 12x+4x+120-6x=300\r<BR>\n" );
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document.write( "10x=180 __ x=18\r<BR>\n" );
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document.write( "2x=36\r<BR>\n" );
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document.write( "60-3x=6 </SPAN>\n" );
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