document.write( "Question 22166: It says perform the indicated operation. How do I do this\r
\n" ); document.write( "\n" ); document.write( "(x+2)(x^2-3x+8)\r
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Algebra.Com's Answer #10707 by queenofit(120)\"\" \"About 
You can put this solution on YOUR website!
I do these different than most people. You are multiplying these numbers together, so use x+2 and multiply the x by each number/variable in the second equation then multiply the 2 by each number/variable in the second equation. then do the adding and subtraction of the common factors.\r
\n" ); document.write( "\n" ); document.write( "like I said I do it different, I do it like long multiplication, it makes it easier for me and I will show you how...maybe it will help... \r
\n" ); document.write( "\n" ); document.write( " x^2-3x+8 multiply just like you would
\n" ); document.write( "* x+2 with all numbers in the equation
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\n" ); document.write( " 2x^2-6x+16 make sure you line up with the
\n" ); document.write( " x^3 -3x^2+8x same type of number or variable
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\n" ); document.write( " x^3-x^2+2x+16
\n" ); document.write( "you can do this problem in the other form that is usually taught,
\n" ); document.write( "(x+2)(x^2-3x+8)
\n" ); document.write( "take the x and multiply each number in the second equation by x
\n" ); document.write( " x*x^2 is x^3 x*(-3x)=-3x^2 x*8=8x
\n" ); document.write( "by 2
\n" ); document.write( " x^2*2=2x^2 2*(-3x)=-6x x*8=16
\n" ); document.write( "so you have x^3-3x^2-8x+2x^2-6x+16
\n" ); document.write( "combine the common factors and you have x^3-3x^2+2x^2-6x+8x+16=
\n" ); document.write( "x^3-x^2+2x+16\r
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