document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22134>Question 22134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> form a sequence that has two arithmetic means between -2 and 58.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10702 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET THE 2 A.M.S BE X,Y...HENCE -2,X,Y,58 ARE IN A.P.WE FIND THAT 58 IS THE FOURTH TERM OR N=4 ,  A=-2 AND D=?...USING TN=A+(N-1)D,WE GET....<BR>\n" );
document.write( " T4=A+(4-1)D<BR>\n" );
document.write( "58=-2+3D<BR>\n" );
document.write( "3D=58+2=60<BR>\n" );
document.write( "D=20<BR>\n" );
document.write( "SO X=-2+1D=-2+20=18<BR>\n" );
document.write( "Y=-2+2D=-2+2*20=38<BR>\n" );
document.write( "SO THE 2 A.MS ARE 18 AND 38 </SPAN>\n" );
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