document.write( "Question 146340: I really need help with this question\r
\n" ); document.write( "\n" ); document.write( "\"I+really+need+help+with+this+question%0D%0A%0D%0A\" log(12,2)+log(12,18)+log(12,4)=x
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Algebra.Com's Answer #107002 by aswathytony(47)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( " log(a,m) + log(a,n) = log(a, m*n)\r
\n" ); document.write( "\n" ); document.write( " log(12,2) + log(12,18) + log( 12,4) = x
\n" ); document.write( " log (12, 2*18*4) = x
\n" ); document.write( " log(12, 144) = x.\r
\n" ); document.write( "\n" ); document.write( " log( m,n) =x then n= m^x.
\n" ); document.write( " i.e. 144 = 12^x
\n" ); document.write( " 12^2 = 12^x
\n" ); document.write( " i.e. x= 2.
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