document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146480>Question 146480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using properties of exponents to simplify-write with positive exponents.\r<BR>\n" );
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document.write( "x^3/7 -  x^1/5  divided by   x^-1/2\r<BR>\n" );
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document.write( "I have no clue where to start, but I thought I would start by trying to get a common denom of the exponents which I thought would be 35.  I am lost!  \r<BR>\n" );
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document.write( "Thanks so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106980 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using properties of exponents to simplify-write with positive exponents.\r<BR>\n" );
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document.write( "x^3/7 -  x^1/5  divided by   x^-1/2<BR>\n" );
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document.write( "x^-(1/2) is a common denominator to each of the numerator terms:\r<BR>\n" );
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document.write( "=  [x^(3/7)/x^(-1/2)] - [x^(1/5)/x^(-1/2)]\r<BR>\n" );
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document.write( "Subtract the denominator exponents from the numerator exponents to get:\r<BR>\n" );
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document.write( "= x^(3/7 + 1/2) - x^(1/5 + 1/2)\r<BR>\n" );
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document.write( "= x^(13/6) - x^(7/10)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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