document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146536>Question 146536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You are driving on a road that has a 6% uphill grade. This means the slope of the hill is 6 over 100. Approximate the amount of verticle change in your position if you drive 200 feet.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106977 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can think of this a problem in proportion.<BR>\n" );
document.write( "The grade, as you say, is 6/100 -- which is the slope defined as rise/run.<BR>\n" );
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document.write( "Therefore our proportion is: (where x is the \"vertical\" rise)<BR>\n" );
document.write( "6/100 = x/200<BR>\n" );
document.write( "(6*200)/100 = x<BR>\n" );
document.write( "12 feet = x<BR>\n" );
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