document.write( "Question 146493: hello again guys...!Here's my question:\r
\n" ); document.write( "\n" ); document.write( "A vertical pole was broken by the wind. The upper part, still attached, reached a point on the level ground 15 feet from the base. If the upper part is 9 feet longer than the lower part, how tall was the pole?
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Algebra.Com's Answer #106943 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
15^2+X^2=(X+9)^2
\n" ); document.write( "225+X^2=X^2+18X+81
\n" ); document.write( "18X=225-81
\n" ); document.write( "18X=144
\n" ); document.write( "X=144/18
\n" ); document.write( "X=8 FEET FOR THE LOWER PART OF THE POLE.
\n" ); document.write( "8+9=17 FEET FOR THE UPPER PART OF THE POLE.
\n" ); document.write( "PROOF:
\n" ); document.write( "15^2+8^2=17^2
\n" ); document.write( "225+64=289
\n" ); document.write( "289=289
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