document.write( "Question 146518: The total cost(in dollars) for a company to manufacture and sell x items per week is:C=0.6xsq-140x+6200
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document.write( "and the revenue (in dollars)by selling all x items is:
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document.write( " R=-0.4xsq+130
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document.write( "How many items must be sold to obtain a weekly profit of $10000?
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document.write( "Thank you
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document.write( "Nicole \n" );
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Algebra.Com's Answer #106932 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! C=0.6xsq-140x+6200 \n" ); document.write( "R=-0.4xsq+130 \n" ); document.write( "profit=revenue-cost. \n" ); document.write( "10,000=-.4x^2+130-(0.6x^2-140x+6,200) \n" ); document.write( "10,000=-.4x^2+130-.6x^2+140x-6,200 \n" ); document.write( "x^2-140x+10,000-6,200-130=0 \n" ); document.write( "x^2-140x+3,670=0 \n" ); document.write( "using the quadratic equation we get: \n" ); document.write( "x=(140+-sqrt[-140^2-4*1*3,670/2*1 \n" ); document.write( "x=(140+-sqrt[19,600-14,680)/2 \n" ); document.write( "x=(140+-sqrt[4,920]/2 \n" ); document.write( "x=(140+-70.14)/2 \n" ); document.write( "x=(140+70.14)/2 \n" ); document.write( "x=210.14/2 \n" ); document.write( "x=105.07 answer. \n" ); document.write( "x=(140-70.14)/2 \n" ); document.write( "x=69.86/2 \n" ); document.write( "x=34.9 answer. \n" ); document.write( " \n" ); document.write( " |