document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22137>Question 22137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log2x+log2(x-6)=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10693 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i assume the 2 is the base of the log. You should explain. I shall leave the 2 out, for ease of writing...\r<BR>\n" );
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document.write( "log(x)+log(x-6)=4\r<BR>\n" );
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document.write( "To remove log-base 2, we need to raise the left and right hand terms to power 2. We can only do that easily when we have 1 term on both sides, so first we re-write the equation as:\r<BR>\n" );
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document.write( "log((x)(x-6))=4\r<BR>\n" );
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document.write( "And now we raise to power 2, giving\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%29%28x-6%29=4%5E2 ALIGN=MIDDLE  ALT=\"%28x%29%28x-6%29=4%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2-6x=16 ALIGN=MIDDLE  ALT=\"x%5E2-6x=16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2-6x-16+=+0 ALIGN=MIDDLE  ALT=\"x%5E2-6x-16+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "(x-8)(x+2) = 0\r<BR>\n" );
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document.write( "so either x=8 or x=-2\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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