document.write( "Question 146464: I need some help with some homework Please!!!!
\n" ); document.write( " The directions say: Solve the following polynomial equations using the zero factor property\r
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\n" ); document.write( "\n" ); document.write( "3x^2 + 5x-2=0\r
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\n" ); document.write( "\n" ); document.write( "2y^2-11y-40=0 thanks so much!!!! \n" ); document.write( "

Algebra.Com's Answer #106929 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!
I need some help with some homework Please!!!!
\n" ); document.write( "The directions say: Solve the following polynomial equations using the zero factor property
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document.write( "Multiply the first number, 3, on the left by the last\r\n" );
document.write( "number on the left, 2. (Take these as positive).\r\n" );
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document.write( "You get 6.  So we write down all the ways to get\r\n" );
document.write( "two integers that have product 6.  These are\r\n" );
document.write( "\r\n" );
document.write( " products   \r\n" );
document.write( "1 x 6 = 6    \r\n" );
document.write( "2 x 3 = 6    \r\n" );
document.write( "\r\n" );
document.write( "Now look at the sign of the last number in\r\n" );
document.write( " = 0, -2.  It is negative, so out beside \r\n" );
document.write( "the multiplication, subtract the smaller of the \r\n" );
document.write( "factors from the larger factor: \r\n" );
document.write( "\r\n" );
document.write( "[Note: if that last sign had been positive, we would add,\r\n" );
document.write( "not subtract.]\r\n" );
document.write( "\r\n" );
document.write( " products   differences\r\n" );
document.write( "1 x 6 = 6    6 - 1 = 5\r\n" );
document.write( "2 x 3 = 6    3 - 2 = 1 \r\n" );
document.write( "\r\n" );
document.write( " = 0\r\n" );
document.write( "\r\n" );
document.write( "Since the middle number 5 appears as a difference\r\n" );
document.write( "between 6 and 1, we use 6 and 1 to rewrite the\r\n" );
document.write( "middle term \"\".\r\n" );
document.write( "\r\n" );
document.write( "We rewrite  as \r\n" );
document.write( "\r\n" );
document.write( "So  = 0\r\n" );
document.write( "\r\n" );
document.write( "becomes\r\n" );
document.write( "\r\n" );
document.write( " = 0\r\n" );
document.write( "\r\n" );
document.write( "Now factor 3x out of the first two terms on the left:\r\n" );
document.write( "\r\n" );
document.write( " = 0\r\n" );
document.write( "\r\n" );
document.write( "Now factor -1 out of the last two terms on the left:\r\n" );
document.write( "\r\n" );
document.write( " = 0\r\n" );
document.write( "\r\n" );
document.write( "Now factor out the binomial factor \r\n" );
document.write( "\r\n" );
document.write( " = 0\r\n" );
document.write( "\r\n" );
document.write( "Set  which gives solution \r\n" );
document.write( "\r\n" );
document.write( "Set  which gives solution \r\n" );
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document.write( "--------------------------------------------\r\n" );
document.write( " \r\n" );
document.write( "  \r\n" );
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document.write( "Multiply the first number, 2, on the left by the last \r\n" );
document.write( "number on the left, 40.\r\n" );
document.write( "(Take these as positive).\r\n" );
document.write( "\r\n" );
document.write( "You get 80.  So we write down all the ways to get\r\n" );
document.write( "two integers that have product 80.  These are\r\n" );
document.write( "\r\n" );
document.write( " products   \r\n" );
document.write( "1 x 80 = 80    \r\n" );
document.write( "2 x 40 = 80    \r\n" );
document.write( "4 x 20 = 80\r\n" );
document.write( "5 x 16 = 80\r\n" );
document.write( "8 x 10 = 80\r\n" );
document.write( "\r\n" );
document.write( "Now look at the sign of the last number in\r\n" );
document.write( " = 0, -2.  It is negative, so out beside \r\n" );
document.write( "the multiplication, subtract the smaller of the \r\n" );
document.write( "factors from the larger factor: \r\n" );
document.write( "\r\n" );
document.write( "[Note: if that last sign had been positive, we would add,\r\n" );
document.write( "not subtract.]\r\n" );
document.write( "\r\n" );
document.write( " products      differences\r\n" );
document.write( "1 x 80 = 80    80 - 1 = 79    \r\n" );
document.write( "2 x 40 = 80    40 - 2 = 38\r\n" );
document.write( "4 x 20 = 80    20 - 4 = 16\r\n" );
document.write( "5 x 16 = 80    16 - 5 = 11\r\n" );
document.write( "8 x 10 = 80    10 - 8 = 2\r\n" );
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document.write( " = 0\r\n" );
document.write( "\r\n" );
document.write( "Since the middle number 11 appears as a difference\r\n" );
document.write( "between 16 and 5, we use 16 and 5 to rewrite the\r\n" );
document.write( "middle term \"\".\r\n" );
document.write( "\r\n" );
document.write( "We rewrite  as \r\n" );
document.write( "\r\n" );
document.write( "So  = 0\r\n" );
document.write( "\r\n" );
document.write( "becomes\r\n" );
document.write( "\r\n" );
document.write( " = 0\r\n" );
document.write( "\r\n" );
document.write( "Now factor 2y out of the first two terms on the left:\r\n" );
document.write( "\r\n" );
document.write( " = 0\r\n" );
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document.write( "Now factor +5 out of the last two terms on the left:\r\n" );
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document.write( " = 0\r\n" );
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document.write( "Now factor out the binomial factor \r\n" );
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document.write( " = 0\r\n" );
document.write( "\r\n" );
document.write( "Set  which gives solution \r\n" );
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document.write( "Set  which gives solution \r\n" );
document.write( "\r\n" );
document.write( "Edwin

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