document.write( "Question 146512This question is from textbook Algebra 1 An Incremental Development
\n" ); document.write( ": Multiply: (3x-5)(7x-5) \n" ); document.write( "
Algebra.Com's Answer #106921 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"%283x-5%29%287x-5%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283x%29-5%29%28highlight%287x%29-5%29\" Multiply the First terms:\"%283%2Ax%29%2A%287%2Ax%29=21%2Ax%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283x%29-5%29%287x%2Bhighlight%28-5%29%29\" Multiply the Outer terms:\"%283%2Ax%29%2A%28-5%29=-15%2Ax\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%2Bhighlight%28-5%29%29%28highlight%287x%29-5%29\" Multiply the Inner terms:\"%28-5%29%2A%287%2Ax%29=-35%2Ax\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%2Bhighlight%28-5%29%29%287x%2Bhighlight%28-5%29%29\" Multiply the Last terms:\"%28-5%29%2A%28-5%29=25\".\r
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\n" ); document.write( "\n" ); document.write( "\"21%2Ax%5E2-15%2Ax-35%2Ax%2B25\" Now collect every term to make a single expression.\r
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\n" ); document.write( "\n" ); document.write( "\"21%2Ax%5E2-50%2Ax%2B25\" Now combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"%283x-5%29%287x-5%29\" FOILS to \"21%2Ax%5E2-50%2Ax%2B25\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%283x-5%29%287x-5%29=21%2Ax%5E2-50%2Ax%2B25\".\r
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