document.write( "Question 146459: A plane is flying a 3547-mile trip from City A to City B. It is flying with a 60-mph tailwind. The flight's point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B. If the speed of the plane in still air is 350 mph, how far from City A is the point of no return? Round to the nearest mile. \n" ); document.write( "
Algebra.Com's Answer #106915 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A plane is flying a 3547-mile trip from City A to City B. \n" ); document.write( "It is flying with a 60-mph tailwind. \n" ); document.write( "The flight's point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B. \n" ); document.write( "If the speed of the plane in still air is 350 mph, how far from City A is the point of no return? \n" ); document.write( "Round to the nearest mile. \n" ); document.write( "-------- \n" ); document.write( "With the wind DATA from A: \n" ); document.write( "Rate = 350+60 = 410 mph ; distance = \"x\" miles ; time = d/r = x/410 hrs. \n" ); document.write( "------------------- \n" ); document.write( "Against the wind DATA: \n" ); document.write( "Rate=350-60 = 290 mph; distance = \"3547-x\" miles ; time = d/r = (3547-x)/290 hrs \n" ); document.write( "--------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "time = time \n" ); document.write( "x/410 = (3547-x)/290 \n" ); document.write( "290x = 410*3547-410x \n" ); document.write( "700x = 1454270 \n" ); document.write( "x = 2077.53 miles \n" ); document.write( "3547-2077.53 = 1469.47 miles from A (pt. of no return) \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |