document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146344>Question 146344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a circle with radius 5 and centered at (3,-1).\r<BR>\n" );
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document.write( "a. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2-9x%2B2y-15=0 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2-9x%2B2y-15=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "b. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2-6x%2B2y%2B15=0 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2-6x%2B2y%2B15=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "c. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2-6x%2B2y-15=0 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2-6x%2B2y-15=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "d. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Find+the+equation+of+a+circle+with+radius+5+and+centered+at+%283%2C-1%29.%0D%0A%0D%0Aa.+%3CIMG+SRC=%2Fcgi-bin%2Fplot-formula.mpl%3Fexpression=x%255E2%252By%255E2-9x%252B2y-15=0+ALIGN=MIDDLE++ALT=%22x%255E2%252By%255E2-9x%252B2y-15=0%22++ DISABLED_style= %22max-width%3A90%25%3B+height%3Aauto%3B%22+%3E%0D%0Ab.+%3CIMG+SRC=%2Fcgi-bin%2Fplot-formula.mpl%3Fexpression=x%255E2%252By%255E2-6x%252B2y%252B15=0+ALIGN=MIDDLE++ALT=%22x%255E2%252By%255E2-6x%252B2y%252B15=0%22++ DISABLED_style= %22max-width%3A90%25%3B+height%3Aauto%3B%22+%3E%0D%0Ac.+%3CIMG+SRC=%2Fcgi-bin%2Fplot-formula.mpl%3Fexpression=x%255E2%252By%255E2-6x%252B2y-15=0+ALIGN=MIDDLE++ALT=%22x%255E2%252By%255E2-6x%252B2y-15=0%22++ DISABLED_style= %22max-width%3A90%25%3B+height%3Aauto%3B%22+%3E%0D%0Ad.+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >x^2+y^2+6x-2y+15=0}}<BR>\n" );
document.write( "e.  nota\r<BR>\n" );
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document.write( "i have no idea where to start ... thank you for your help in advance<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106880 by </B><A HREF=/tutors/aboutme.mpl?userid=aswathytony><B>aswathytony(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aswathytony><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equation of circle with centre (h,k) and radius r is ( x -h)^2 +(y-k)^2= r^2.\r<BR>\n" );
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document.write( "here centre (h,k) = (3, -1) , r =5.\r<BR>\n" );
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document.write( "substituting these values in the equation we get,<BR>\n" );
document.write( "  (x - 3)^2 + (y - (-1))^2 = 5^2<BR>\n" );
document.write( "  (x-3)^2 + ( y + 1)^2 = 25<BR>\n" );
document.write( "  x^2 -6x +9 + y^2 + 2y + 1 =25<BR>\n" );
document.write( "  x^2 + y^2 - 6x +2y+ 9+1 - 25 =0\r<BR>\n" );
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document.write( "  x^2 + y^2 - 6x + 2y -15 = 0 </SPAN>\n" );
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