document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146348>Question 146348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sum of(1+2+4+8+16+.........30th term) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106878 by </B><A HREF=/tutors/aboutme.mpl?userid=aswathytony><B>aswathytony(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aswathytony><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is a G.P.( Geometric progression)<BR>\n" );
document.write( "sum of n terms of a G.P = a( r^n -1 )/r -1\r<BR>\n" );
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document.write( "1 + 2 + 4 + 8 +16 +....+30th term\r<BR>\n" );
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document.write( "first term ,a = 1<BR>\n" );
document.write( "common ratio, r = 2 <BR>\n" );
document.write( "number of terms, n =30\r<BR>\n" );
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document.write( "substituting in formula, sum of 30terms = 1 ( 2^30 - 1) / 2-1<BR>\n" );
document.write( "                                        = 2^30 -1 /1<BR>\n" );
document.write( "                                        = 2^30 - 1 </SPAN>\n" );
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