document.write( "Question 146357: Please evalute complex expression with final solution in standard form (a+bi);
\n" ); document.write( "(2+3i)/ (-4+3i)
\n" ); document.write( "Thank You \n" ); document.write( "
Algebra.Com's Answer #106856 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
If you started with:
\n" ); document.write( "(2+3i)
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\n" ); document.write( "(-4+3i)
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\n" ); document.write( "The first thing you'd like to do is eliminate the i's from the bottom (denominator). Do this by multiplying numerator and denominator by (-4-3i).
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\n" ); document.write( "(2+3i) (-4-3i)
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\n" ); document.write( "(-4+3i) (-4-3i)
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\n" ); document.write( "using \"FOIL\" multiply out the numerator and denominator to get:
\n" ); document.write( "(-8-6i-12i+9)
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\n" ); document.write( "(16+12i-12i+9)
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\n" ); document.write( "combining like-terms we get:
\n" ); document.write( "(-8-18i+9)
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\n" ); document.write( "(16+9)
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\n" ); document.write( "(1-18i)
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\n" ); document.write( " 25
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\n" ); document.write( "Now, the problem asked you to put it in a+bi form:
\n" ); document.write( "1/25(1-18i) = (1/25) - (18/25)i\r
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