document.write( "Question 22152: Find the real-number solutions of the equation: $\"2x%5E3-6x%5E2=0\"$ \n" ); document.write( "

Algebra.Com's Answer #10683 by Earlsdon(6294) $\"\"$ $\"About$

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Solve for x:
\n" ); document.write( " $\"2x%5E3+-+6x%5E2+=+0\"$ Factor 2x^2
\n" ); document.write( " $\"2x%5E2%28x+-+3%29\"$ Apply the zero product principle.
\n" ); document.write( " $\"2x%5E2+=+0\"$ and/or $\"x+-+3+=+0\"$
\n" ); document.write( "If $\"2x%5E2+=+0\"$ then, $\"x+=+0\"$
\n" ); document.write( "If $\"x+-+3+=+0\"$ then, $\"x+=+3\"$
\n" ); document.write( "The solutions are:
\n" ); document.write( "x = 0 (A double root)
\n" ); document.write( "x = 3 \n" ); document.write( "

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