document.write( "Question 146307: An astronaut on the moon tosses a ball upwards; when will the ball initially be 35 feet above the lunar surface if the ball's height (feet) follows: h(t)=-2.6t^2+32.1t_5.5, and t is in seconds from release?
\n" ); document.write( "a)1 second
\n" ); document.write( "b)2 seconds
\n" ); document.write( "c)1/2 seconds
\n" ); document.write( "d)13.2 seconds\r
\n" ); document.write( "\n" ); document.write( "I came up with 1 second and 11.. a little confused.
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Algebra.Com's Answer #106829 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
An astronaut on the moon tosses a ball upwards; when will the ball initially be 35 feet above the lunar surface if the ball's height (feet) follows:
\n" ); document.write( "h(t)=-2.6t^2+32.1t_5.5, and t is in seconds from release?
\n" ); document.write( "a)1 second
\n" ); document.write( "b)2 seconds
\n" ); document.write( "c)1/2 seconds
\n" ); document.write( "d)13.2 seconds
\n" ); document.write( "-------------------
\n" ); document.write( "-2.6t^2 + 32.1t + 5.5 = 35
\n" ); document.write( "-2.6t^2 + 32.1t -29.5 = 0
\n" ); document.write( "----------
\n" ); document.write( "The 1st time the ball reaches 35 ft. (on the way up) is 1 second.
\n" ); document.write( "The 2nd time it reaches 35 ft. (on the way down) is 11.35 seconds
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "
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