document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146308>Question 146308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 10-1/t=9/t^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106827 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10-1/t=9/t^2<BR>\n" );
document.write( "10t^2-t=9 Multiply each side by LCM to eliminate fractions.<BR>\n" );
document.write( "10t^2-t-9=0<BR>\n" );
document.write( "10*-9=-90 What 2 factors of -90=-1? Ans: -10 & 9<BR>\n" );
document.write( "10t^2-10t+9t-9=0<BR>\n" );
document.write( "10t(t-1)+9(t-1)=0 Factoring by grouping.<BR>\n" );
document.write( "(10t+9)(t-1)=0<BR>\n" );
document.write( "10t=-9<BR>\n" );
document.write( "t=-9/10<BR>\n" );
document.write( "t=1<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
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