document.write( "Question 146261: how would i do this?
\n" ); document.write( "Factor the following polynomial completely.\r
\n" ); document.write( "\n" ); document.write( "y2 + 12y + 36=
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Algebra.Com's Answer #106795 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Looking at \"y%5E2%2B12y%2B36\" we can see that the first term is \"y%5E2\" and the last term is \"36\" where the coefficients are 1 and 36 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient 36 to get 36. Now what two numbers multiply to 36 and add to the middle coefficient 12? Let's list all of the factors of 36:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 36:\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,9,12,18\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-9,-12,-18 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 36\r
\n" ); document.write( "\n" ); document.write( "1*36\r
\n" ); document.write( "\n" ); document.write( "2*18\r
\n" ); document.write( "\n" ); document.write( "3*12\r
\n" ); document.write( "\n" ); document.write( "4*9\r
\n" ); document.write( "\n" ); document.write( "6*6\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-36)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(-18)\r
\n" ); document.write( "\n" ); document.write( "(-3)*(-12)\r
\n" ); document.write( "\n" ); document.write( "(-4)*(-9)\r
\n" ); document.write( "\n" ); document.write( "(-6)*(-6)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 12? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 12\r
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First NumberSecond NumberSum
1361+36=37
2182+18=20
3123+12=15
494+9=13
666+6=12
-1-36-1+(-36)=-37
-2-18-2+(-18)=-20
-3-12-3+(-12)=-15
-4-9-4+(-9)=-13
-6-6-6+(-6)=-12
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 6 and 6 add up to 12 and multiply to 36\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"y%5E2%2B12y%2B36\", replace \"12y\" with \"6y%2B6y\" (notice \"6y%2B6y\" adds up to \"12y\". So it is equivalent to \"12y\")\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2%2Bhighlight%286y%2B6y%29%2B36\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"y%5E2%2B6y%2B6y%2B36\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%5E2%2B6y%29%2B%286y%2B36%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"y%28y%2B6%29%2B6%28y%2B6%29\" Factor out the GCF of \"y\" out of the first group. Factor out the GCF of \"6\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B6%29%28y%2B6%29\" Since we have a common term of \"y%2B6\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"y%5E2%2B6y%2B6y%2B36\" factors to \"%28y%2B6%29%28y%2B6%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"y%5E2%2B12y%2B36\" factors to \"%28y%2B6%29%28y%2B6%29\" (since \"y%5E2%2B12y%2B36\" is equivalent to \"y%5E2%2B6y%2B6y%2B36\")\r
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\n" ); document.write( "\n" ); document.write( "note: \"%28y%2B6%29%28y%2B6%29\" is equivalent to \"%28y%2B6%29%5E2\" since the term \"y%2B6\" occurs twice. So \"y%5E2%2B12y%2B36\" also factors to \"%28y%2B6%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"y%5E2%2B12y%2B36\" factors to \"%28y%2B6%29%5E2\"
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