document.write( "Question 146233: find two consecuive positive integers if the difference of their reciprocals is 1/12 \n" ); document.write( "
Algebra.Com's Answer #106769 by nabla(475)\"\" \"About 
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a
\n" ); document.write( "a+1\r
\n" ); document.write( "\n" ); document.write( "\"1%2Fa+-+1%2F%28a%2B1%29=1%2F12\"
\n" ); document.write( "\"%28a%2B1-a%29%2F%28a%28a%2B1%29%29=1%2F12\"
\n" ); document.write( "\"1%2F%28a%28a%2B1%29%29=1%2F12\"\r
\n" ); document.write( "\n" ); document.write( "This implies\r
\n" ); document.write( "\n" ); document.write( "\"%28a%28a%2B1%29%29=12\"
\n" ); document.write( "\"a%5E2%2Ba-12=0\"
\n" ); document.write( "\"%28a%2B4%29%28a-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "Gives a=-4 or a=3, a must be positive so we exclude -4 from the answer set.
\n" ); document.write( "So the numbers are 3, 3+1=4\r
\n" ); document.write( "\n" ); document.write( "Now, check:
\n" ); document.write( "1/3 -1/4=4/12 -3/12=1/12.
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