document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146222>Question 146222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor: 4p^2 - 8p - 60 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106767 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, all terms have a 4 in common, factor that out first.\r<BR>\n" );
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document.write( "4p^2 - 8p - 60=4(p^2-2p-15)\r<BR>\n" );
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document.write( "Now, we need two numbers that multiply to get -15 but ADD to get -2. These would be -5 and 3.\r<BR>\n" );
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document.write( "So,<BR>\n" );
document.write( "4(p^2-2p-15)=4(p-5)(p+3) </SPAN>\n" );
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