document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146219>Question 146219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/8X + 1/4y=5<BR>\n" );
document.write( "1/16x +1/2y=7<BR>\n" );
document.write( "Solve system with addition method.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106766 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, multiply the first equation by -(1/2).\r<BR>\n" );
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document.write( "That gives:<BR>\n" );
document.write( "(-1/16)x-(1/8)y=-5/2<BR>\n" );
document.write( "(1/16)x+(1/2)y=7\r<BR>\n" );
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document.write( "Now we can add them.\r<BR>\n" );
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document.write( "(3/8)y=9/2<BR>\n" );
document.write( "y=72/6=12.\r<BR>\n" );
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document.write( "Now for x:<BR>\n" );
document.write( "(1/16)x+6=7<BR>\n" );
document.write( "x=16\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "2+3=5<BR>\n" );
document.write( "1+6=7.\r<BR>\n" );
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