document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146221>Question 146221</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.5x-2y=-0.25<BR>\n" );
document.write( "3x+1.5y=6.375\r<BR>\n" );
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document.write( "Solve with addition method<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106765 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106765\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, multiply the first equation by -2.\r<BR>\n" );
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document.write( "giving<BR>\n" );
document.write( "-3x+4y=.5<BR>\n" );
document.write( "3x+1.5y=6.375\r<BR>\n" );
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document.write( "Now we can add them.<BR>\n" );
document.write( "5.5y=6.875<BR>\n" );
document.write( "y=1.25\r<BR>\n" );
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document.write( "And x must be<BR>\n" );
document.write( "1.5x-2(1.25)=-.25<BR>\n" );
document.write( "1.5x=2.25<BR>\n" );
document.write( "x=1.5\r<BR>\n" );
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document.write( "check:\r<BR>\n" );
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document.write( "1.5(1.5)-2(1.25)=-.25<BR>\n" );
document.write( "3(1.5)+1.5(1.25)=6.375 </SPAN>\n" );
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