document.write( "Question 146199: im sorry if i could get help on this last problem thanks alot!
\n" ); document.write( "which product of factors is equivalent to (x+1)-y? (please note there is a little 2 over on top next to the 1 out of the paranthesis and another little 2 over the y ? THANK YOU AGAIN.
\n" ); document.write( "

Algebra.Com's Answer #106753 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2B1%29%5E2-y%5E2\" Start with the given expression\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let \"a=x%2B1\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"a%5E2-y%5E2\" Replace \"x%2B1\" with \"a\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28a%2By%29%28a-y%29\" Now factor the expression by use of the difference of squares formula. Remember, the difference of squares formula is \"A%5E2-B%5E2=%28A%2BB%29%28A-B%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%2By%29%28x%2B1-y%29\" Replace each \"a\" with \"x%2B1\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%2By%2B1%29%28x-y%2B1%29\" Rearrange the terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"%28x%2B1%29%5E2-y%5E2\" factors to \"%28x%2By%2B1%29%28x-y%2B1%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In other words, \"%28x%2B1%29%5E2-y%5E2=%28x%2By%2B1%29%28x-y%2B1%29\"
\n" ); document.write( "
\n" );