document.write( "Question 146190: Please help to find an equation of the line that passes through (-3,6) and has a slope m = -2.
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Algebra.Com's Answer #106744 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-2\" which goes through the point (-3,6), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-6=%28-2%29%28x--3%29\" Plug in \"m=-2\", \"x%5B1%5D=-3\", and \"y%5B1%5D=6\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-6=%28-2%29%28x%2B3%29\" Rewrite \"x--3\" as \"x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-6=-2x%2B%28-2%29%283%29\" Distribute \"-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-6=-2x-6\" Multiply \"-2\" and \"3\" to get \"-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-2x-6%2B6\" Add 6 to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=-2x%2B0\" Combine like terms \"-6\" and \"6\" to get \"0\" \r
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\n" ); document.write( "\n" ); document.write( "\"y=-2x\" Remove the zero term\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-2\" which goes through the point (\"-3\",\"6\") is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=-2x\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-2\" and the y-intercept is \"b=0\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=-2x\" and plot the point (\"-3\",\"6\"), we get (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=-2x\" through the point (-3,6)\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"-2\" and goes through the point (-3,6), this verifies our answer.
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