document.write( "Question 146189: I am taking a college calculus class afterm some time off and I cannot remember how to solve simplify a polynomial with division.\r
\n" ); document.write( "\n" ); document.write( "It is as follows: [(x+3/x+1)-2]/(x-1). What are the rules to remember and how would I begin solving this? \n" ); document.write( "
Algebra.Com's Answer #106743 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
[(x+3/x+1)-2]/(x-1)\r
\n" ); document.write( "\n" ); document.write( "To simplify the bracket you need a common denominator:\r
\n" ); document.write( "\n" ); document.write( "= [(x+3)/(x+1) - 2(x+1)/(x+1)] / (x-1)\r
\n" ); document.write( "\n" ); document.write( "Now combine the numerators in the bracket to get:\r
\n" ); document.write( "\n" ); document.write( "= [(x+3 -2x-2)/(x+1)] /(x-1)\r
\n" ); document.write( "\n" ); document.write( "= [(-x+1)/(x+1)]/(x-1) \r
\n" ); document.write( "\n" ); document.write( "Now, invert the denominator and change to multiplication:\r
\n" ); document.write( "\n" ); document.write( "= [-(x-1)/(x+1)] * [ 1/(x-1)]\r
\n" ); document.write( "\n" ); document.write( "Cancel any factor that is common to a numerator and a denominator to get:\r
\n" ); document.write( "\n" ); document.write( "= [-1/(x+1)]\r
\n" ); document.write( "\n" ); document.write( "= -1/(x^2-1)\r
\n" ); document.write( "\n" ); document.write( "=====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "= [
\n" ); document.write( " \n" ); document.write( "
\n" );