document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22140>Question 22140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice the lesser of two consecutive intergers is 12 less than 3 times the greater interger.  Find the lesser integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10674 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the first consecutive integers and let x+1 be the next<BR>\n" );
document.write( "2(x)=3(x+1)-12<BR>\n" );
document.write( "2x=3x+3-12<BR>\n" );
document.write( "-x=-9<BR>\n" );
document.write( "x=9<BR>\n" );
document.write( "9+1=10<BR>\n" );
document.write( "Hence, the two consecutive integers are 9 and 10.\r<BR>\n" );
document.write( "\n" );
document.write( "Check:<BR>\n" );
document.write( "2(9)=3(10)-12<BR>\n" );
document.write( "18=18 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );