document.write( "Question 146182: Hello, I need a little help with the following.\r
\n" ); document.write( "\n" ); document.write( "Square root of 3x+1 - square root of x+1 = 2. I have tried solving this by isoloating the x+1 square root term, but keep getting a no solution answer, which is not correct. If someone could provide me the steps on how to get the correct answer, so I can learn the steps myself, that would be much appreciated.\r
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Algebra.Com's Answer #106739 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Sqrt(3x+1) - sqrt(x+1) = 2.
\n" ); document.write( "sqrt(3x+1) = 2 + sqrt(x+1)
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "3x+1 = 4 + 4sqrt(x+1) + x+1
\n" ); document.write( "2x = 4 + 4sqrt(x+1)
\n" ); document.write( "x-2 = 2sqrt(x+1)
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x^2 -4x+4 = 4x+4
\n" ); document.write( "x^2-8x = 0
\n" ); document.write( "x(x-8) = 0
\n" ); document.write( "x = 0 or x = 8
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\n" ); document.write( "Checking:
\n" ); document.write( "x=0?
\n" ); document.write( "sqrt(1) - sqrt(1) = 2; Wrong
\n" ); document.write( "--------
\n" ); document.write( "x=8?
\n" ); document.write( "sqrt(25) - sqrt(9) = 2
\n" ); document.write( "5-3=2 ; Correct
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\n" ); document.write( "Final Solution: x=8
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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