document.write( "Question 146182: Hello, I need a little help with the following.\r
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document.write( "Square root of 3x+1 - square root of x+1 = 2. I have tried solving this by isoloating the x+1 square root term, but keep getting a no solution answer, which is not correct. If someone could provide me the steps on how to get the correct answer, so I can learn the steps myself, that would be much appreciated.\r
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Algebra.Com's Answer #106739 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Sqrt(3x+1) - sqrt(x+1) = 2. \n" ); document.write( "sqrt(3x+1) = 2 + sqrt(x+1) \n" ); document.write( "Square both sides to get: \n" ); document.write( "3x+1 = 4 + 4sqrt(x+1) + x+1 \n" ); document.write( "2x = 4 + 4sqrt(x+1) \n" ); document.write( "x-2 = 2sqrt(x+1) \n" ); document.write( "Square both sides to get: \n" ); document.write( "x^2 -4x+4 = 4x+4 \n" ); document.write( "x^2-8x = 0 \n" ); document.write( "x(x-8) = 0 \n" ); document.write( "x = 0 or x = 8 \n" ); document.write( "----------------- \n" ); document.write( "Checking: \n" ); document.write( "x=0? \n" ); document.write( "sqrt(1) - sqrt(1) = 2; Wrong \n" ); document.write( "-------- \n" ); document.write( "x=8? \n" ); document.write( "sqrt(25) - sqrt(9) = 2 \n" ); document.write( "5-3=2 ; Correct \n" ); document.write( "------------------ \n" ); document.write( "Final Solution: x=8 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |