document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146158>Question 146158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106712 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106712\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use a combination. See http://www.mathagonyaunt.co.uk/STATISTICS/ESP/Perms_combs.html\r<BR>\n" );
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document.write( "15P6 =  15!/((15-6)!  * 6!) <BR>\n" );
document.write( "= (15*14*13*12*11*10)/ (6*5*4*3*2*1)<BR>\n" );
document.write( "= (14*13*11*10)/4<BR>\n" );
document.write( "= 7*13*11*5<BR>\n" );
document.write( "= 5005 </SPAN>\n" );
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