document.write( "Question 146114: Donna invested her $33,000 bonus and received a total of $970 in interest after 1 year. If part of her money returned 4% and the remainder 2.25% then how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #106674 by ankor@dixie-net.com(22740)\"\" \"About 
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Donna invested her $33,000 bonus and received a total of $970 in interest after 1 year. If part of her money returned 4% and the remainder 2.25% then how much did she invest at each rate?
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\n" ); document.write( "Let x = amt invested at 4%
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\n" ); document.write( "The total invested was given as 33000, therefore:
\n" ); document.write( "(33000-x) = amt invested at 2.25%
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\n" ); document.write( "Int at 4% + int at 2.25% = $970
\n" ); document.write( ".04x + .0225(33000-x) = 970
\n" ); document.write( ":
\n" ); document.write( ".04x + 742.5 - .0225x = 970
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\n" ); document.write( ".04x - .0225x = 970 - 742.5
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\n" ); document.write( ".0175x = 227.5
\n" ); document.write( "x = \"227.5%2F.0175\"
\n" ); document.write( "x = $13,000 invested at 4%
\n" ); document.write( "and
\n" ); document.write( "33000 - 13000 = $20,000 invested at 2.25%
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\n" ); document.write( "Check solutions
\n" ); document.write( ".04(13000) + .0225(20000) =
\n" ); document.write( " 520 + 450 = 970; confirms our solutions \n" ); document.write( "
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