document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22100>Question 22100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would i solve y=2x+7<BR>\n" );
document.write( "                  y=5x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10667 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The easiest way to do this problem is by substitution.  Take the value for y from the first equation and substitute it for y in the second equation.\r<BR>\n" );
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document.write( "y=5x+4  becomes 2x+7=5x+4<BR>\n" );
document.write( "Solving for x we get x=1<BR>\n" );
document.write( "Now go back and substitute 1 for x in the first equation and solve for y. </SPAN>\n" );
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