document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146102>Question 146102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a number is 7 less than another, if 4 times the smaaler number plus twice the larger is 46. find the two numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106654 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106654\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a number is 7 less than another, if 4 times the smaaler number plus twice the larger is 46. find the two numbers?<BR>\n" );
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document.write( "Let x = smaller number<BR>\n" );
document.write( "then x-7 = larger number (from:\"a number is 7 less than another\")<BR>\n" );
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document.write( "Finally, from \"4 times the smaaler number plus twice the larger is 46\" we get our equation:<BR>\n" );
document.write( "4x + 2(x-7) = 47<BR>\n" );
document.write( "4x + 2x - 14 = 47<BR>\n" );
document.write( "6x - 14 = 47<BR>\n" );
document.write( "6x = 61<BR>\n" );
document.write( "x = 61/6<BR>\n" );
document.write( "x = 10 and 1/6 (smaller number)<BR>\n" );
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document.write( "and, <BR>\n" );
document.write( "x-7 = 61/6 - 7 = 61/6 - 42/6 = 19/6 <BR>\n" );
document.write( "x-7 = 3 and 1/6 (larger number)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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