document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146093>Question 146093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have similar problems to this in our textbook, but this is off a handwritten midterm review from our \"teacher.\" It's an online course. \r<BR>\n" );
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document.write( "A 2004 Pontiac Montana has an engine coolant capacity of 10.1 liters. If the system is currently filled with a mixture that is 30% antifreeze, how much should be drained and replaced with pure antifreeze so the system is filled with  a mix that is 50% pure antifreeze? <BR>\n" );
document.write( "The answer we have is 2.89. I do not understand how to get to this answer! HELP! :) Thanks.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106641 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 2004 Pontiac Montana has an engine coolant capacity of 10.1 liters. If the system is currently filled with a mixture that is 30% antifreeze, how much should be drained and replaced with pure antifreeze so the system is filled with a mix that is 50% pure antifreeze?<BR>\n" );
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document.write( "Let x = amt in liters drained and replaced by 100% antifreeze<BR>\n" );
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document.write( "amt of 30% antifreeze = 10.1 - x<BR>\n" );
document.write( "amt of 100% antifreeze = x<BR>\n" );
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document.write( "\"half of radiator content\" = amt of anti-freeze<BR>\n" );
document.write( ".5(10.1) = \"amt antifreeze from 30% mix\" + \"amt antifreeze from 100% mix\"<BR>\n" );
document.write( ".5(10.1) = .30(10.1 - x) + x<BR>\n" );
document.write( "5.05 = 3.03 - .30x + x<BR>\n" );
document.write( "5.05 = 3.03 + .70x<BR>\n" );
document.write( "2.02 = .70x<BR>\n" );
document.write( "2.89 liters = x<BR>\n" );
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