document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21993>Question 21993</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It would be nice if someone could show me how to solve this mixture problem. Thanks in advance.\r<BR>\n" );
document.write( "\n" );
document.write( "A 15 liter bucket of soda contains a mixture with a concentration of 50% corn syrup. How much of this mixture x must be withdrawn and replaced by 100% corn syrup to bring the mixture up to a concentration of 60% corn syrup?\r<BR>\n" );
document.write( "\n" );
document.write( "x=________liters </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10664 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 100x+50(15-x)=60(15)<BR>\n" );
document.write( "100x+750-50x=900<BR>\n" );
document.write( "Simplify<BR>\n" );
document.write( "50x=150 (divide both sides 50)<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "Hence for 100% it should bee 3L and for 50% it should be 12L<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );