document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146074>Question 146074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Helen's Health food usually sells 400 cans of Propac per week while price is $5.00 per can. After playing with prices for awhile Helen has determined that the weekly demand can be found by using this equation:  D=600-40P<BR>\n" );
document.write( "where d is cans and p is price per can\r<BR>\n" );
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document.write( "Will Helen sell more or less Propac if she raises the price?<BR>\n" );
document.write( "What happens to her sales every time she raises her price by $1? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106635 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Helen's Health food usually sells 400 cans of Propac per week while price is $5.00 per can. After playing with prices for awhile Helen has determined that the weekly demand can be found by using this equation:  D=600-40P<BR>\n" );
document.write( "where d is cans and p is price per can.  Will Helen sell more or less Propac if she raises the price? What happens to her sales every time she raises her price by $1?\r<BR>\n" );
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document.write( "The slope of the equation is -40<BR>\n" );
document.write( "That means the number of cans sold decreases by 40 for every<BR>\n" );
document.write( "increase of one dollar in the price.<BR>\n" );
document.write( "Try p=0 and then p=1 and see how D changes by -40.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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