document.write( "Question 146071: 5a+24b=109.60
\n" ); document.write( "16a+24b=171
\n" ); document.write( "Have got this far. I understand how to write it in elimination.
\n" ); document.write( "Please show me how to write it correctly in substitution form \n" ); document.write( "
Algebra.Com's Answer #106631 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
5a+24b=109.60
\n" ); document.write( "5a=109.6-24b
\n" ); document.write( "a=109.6/5-24b/5
\n" ); document.write( "now substitute (109.6/5-24b/5) for a in the other equation & solve for b.
\n" ); document.write( "16a+24b=171
\n" ); document.write( "16(109.6/5-24b/5)+24b=171
\n" ); document.write( "1753.6/5-384b/5+24b=171
\n" ); document.write( "-384b/5+24b=171-1753.6/5
\n" ); document.write( "(-384b+5*24b)/5=(5*171-1753.6)/5
\n" ); document.write( "(-384b+120b)/5=(855-1753.6)/5
\n" ); document.write( "264b/5=898.6/5 csncelling out the denominators we have:
\n" ); document.write( "264b=898.6
\n" ); document.write( "b=989.6/264 answer.
\n" ); document.write( "16a+24(898.6/264)=171
\n" ); document.write( "16a+21566.4/264=171
\n" ); document.write( "16a=171-21566.4/264
\n" ); document.write( "16a=(171*264-21566.4)/264
\n" ); document.write( "16a=(45144-21566.4)/264
\n" ); document.write( "16a=23577.6/264
\n" ); document.write( "a=(23577.6/264)(1/16)
\n" ); document.write( "a=23577.6/4224
\n" ); document.write( "a=61.4/11 answer.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );