document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22082>Question 22082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve a problem such as this:<BR>\n" );
document.write( "1) 5(2x-3)+8=9? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10663 by </B><A HREF=/tutors/aboutme.mpl?userid=queenofit><B>queenofit(120)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=queenofit><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you must distribute the number (or variable) in front of the ( ) to the inside of the ( ).  This is done by multiplying 5 times everything in the ( ).  Then just solve for x.  I will work the problem. If you have questions please let me know.\r<BR>\n" );
document.write( "\n" );
document.write( "5(2x-3) + 8 = 9<BR>\n" );
document.write( "10x-15  + 8 = 9<BR>\n" );
document.write( "10x = 15 -8 + 9<BR>\n" );
document.write( "10x = 16<BR>\n" );
document.write( "x = 16/10  = 8/5      this answer will depend on what form your instuctor wants </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );