document.write( "Question 146084This question is from textbook Finite Mathematics
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document.write( ": Please solve the system of equation for all variables using a matrix.
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document.write( "My solution\r
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document.write( "2 1=-4
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document.write( "1 3=9\r
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document.write( "r2 reverse r1
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document.write( "1 3=9
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document.write( "2 1=-4\r
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document.write( "r2* -2
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document.write( "1 3=9
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document.write( "0 -1=-6\r
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document.write( "r2* 2\r
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document.write( "1 3=9
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document.write( "0 1=-12\r
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document.write( "r2*-3+r1
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document.write( "1 0=-6
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document.write( "0 1=-12
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document.write( "x= -6 and y= -12
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document.write( "Please help I'm trying to get these steps, but i think my mutiplcation is off somewhere. Thanks in advance. \n" );
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Algebra.Com's Answer #106625 by budge(1)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Hi, you are literally trying to get the identity on the left hand side of the matrix.\r \n" ); document.write( "\n" ); document.write( "You dont have to swap the rows but if you do then you will have:\r \n" ); document.write( "\n" ); document.write( "1 3 = 9 \n" ); document.write( "-2 1=-4\r \n" ); document.write( "\n" ); document.write( "then to get a zero in row 2 you can add 2 row1:\r \n" ); document.write( "\n" ); document.write( "1 3=9 \n" ); document.write( "0 7=14\r \n" ); document.write( "\n" ); document.write( "then we need a 1 where the 7 is and therefore we divide row 2 by 7:\r \n" ); document.write( "\n" ); document.write( "1 3=9 \n" ); document.write( "0 1=2\r \n" ); document.write( "\n" ); document.write( "Row 1 minus 3 row 2:\r \n" ); document.write( "\n" ); document.write( "1 0=3 \n" ); document.write( "0 1=2\r \n" ); document.write( "\n" ); document.write( "Therfore you read off your solution that x=3 and y=2 because column 1 relates to x and column 2 is y. \n" ); document.write( " \n" ); document.write( " |