document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146039>Question 146039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use either the fundamental counting principle or the permutation formulas (or both) to answer the following:\r<BR>\n" );
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document.write( "The Board of Directors does not have assigned seats in the conference room. If there are 12 of them, seated at a round table, how many different seating arrangements are possible?\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106598 by </B><A HREF=/tutors/aboutme.mpl?userid=BrittanyM><B>BrittanyM(80)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BrittanyM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As soon as we realize how permutations work, this problem is actually quite simple.  We have 12 items to work with, and because arrangement DOES matter, we know that we must use permutation.\r<BR>\n" );
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document.write( "All this is is <BR>\n" );
document.write( "12!\r<BR>\n" );
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document.write( "Which basically means<BR>\n" );
document.write( "12 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1\r<BR>\n" );
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document.write( "so we now know that there are 479001600 different ways that the 12 members can be seated. </SPAN>\n" );
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