document.write( "Question 145994: Train A and B are traveking the same directon on parrallel tracks.Train A is traveling 80mph and Train B is traveling 90 mph. Train A passes a station at 4:20 and Train B passes the same stattion at 4:32. How long will it take for train B to catch up with train A? What time will it be? \n" ); document.write( "
Algebra.Com's Answer #106553 by nerdybill(7384)\"\" \"About 
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Train A and B are traveking the same directon on parrallel tracks.Train A is traveling 80mph and Train B is traveling 90 mph. Train A passes a station at 4:20 and Train B passes the same stattion at 4:32. How long will it take for train B to catch up with train A? What time will it be?
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\n" ); document.write( "Essentially, Train A (the slower train) has a 12 minute head start. 12/60 is .2 hours head start.
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\n" ); document.write( "Let x = hours it takes for train B to catch up
\n" ); document.write( "then
\n" ); document.write( "(x+.2) = time Train A traveled
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\n" ); document.write( "For Train B to catch up with Train A, the distance traveled since the station MUST be the same: d=rt (distance=rate*time)
\n" ); document.write( "80(x+.2) = 90x
\n" ); document.write( "80x + 16 = 90x
\n" ); document.write( "16 = 10x
\n" ); document.write( "1.6 hrs = x (answer to first question)
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\n" ); document.write( "4:20 + 1.6 hrs
\n" ); document.write( ".6 hrs is .6*60= 36min
\n" ); document.write( "therefore, 4:20 + 1:36 = 5:56 \n" ); document.write( "
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