document.write( "Question 145988: 4x+2y=1, 2x+3y=.70 solve for x and y \n" ); document.write( "
Algebra.Com's Answer #106548 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
4x+2y=1, 2x+3y=.70 solve for x and y
\n" ); document.write( ".
\n" ); document.write( "4x+2y= 1
\n" ); document.write( "2x+3y=.70
\n" ); document.write( ".
\n" ); document.write( "multiply the second equation by -2:
\n" ); document.write( " 4x+2y= 1
\n" ); document.write( "-4x-6y=-1.4
\n" ); document.write( ".
\n" ); document.write( "add both equations together:
\n" ); document.write( "-4y = -0.4
\n" ); document.write( "y = 0.1
\n" ); document.write( ".
\n" ); document.write( "plug the value of y (above) into equation 1 and solve for x:
\n" ); document.write( "4x+2y= 1
\n" ); document.write( "4x+2(0.1)= 1
\n" ); document.write( "4x+0.2= 1
\n" ); document.write( "4x = 0.8
\n" ); document.write( "x = 0.2
\n" ); document.write( ".
\n" ); document.write( "(x,y) = (0.2,0.1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );