document.write( "Question 145945: Please help me Form A quadratic equation and help me Discuss the slope or rate of change \r
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Algebra.Com's Answer #106525 by nabla(475)\"\" \"About 
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f(x)=x^2+2x+1 \r
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\n" ); document.write( "\n" ); document.write( "This can also be factored as f(x)=(x+1)^2.
\n" ); document.write( "Moreover, the vertex is at (-1,0), y intercept at f(0)=1.\r
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\n" ); document.write( "\n" ); document.write( "The slope will be f'(x)=2x+2=2(x+1). Thus, the slope is negative until -1 and positive after -1. The further away you go from -1 in either direction, the faster the function will be growing.
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