document.write( "Question 145904This question is from textbook Blitzer College Algebra
\n" ); document.write( ": z=2x+4y
\n" ); document.write( "x>=0, y>=0 Linear programming problem, graphing a solution, and maximum.
\n" ); document.write( "x+3y>=6
\n" ); document.write( "x+y>=3
\n" ); document.write( "x+y<=9\r
\n" ); document.write( "\n" ); document.write( "I come up with serveral vertices. Even when using the example. I know how to put the vertices back into the equations, but I need to figure out how to limit or pick the correct vertices; (0,0), (0,2), (6,0), (0,3), (3,0), (5,4), (6,3), (0,9) My graphe looks like a octagon kind of including 0. I am missing something and trying desperately to understand this. Can someone show me how I conclude which vertices are correct?\r
\n" ); document.write( "\n" ); document.write( "Heidi
\n" ); document.write( "

Algebra.Com's Answer #106481 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
z=2x+4y
\n" ); document.write( "x>=0, y>=0 Linear programming problem, graphing a solution, and maximum.
\n" ); document.write( "x+3y>=6
\n" ); document.write( "x+y>=3
\n" ); document.write( "x+y<=9
\n" ); document.write( "I come up with serveral vertices. Even when using the example. I know how to put the vertices back into the equations, but I need to figure out how to limit or pick the correct vertices; (0,0), (0,2), (6,0), (0,3), (3,0), (5,4), (6,3), (0,9)
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\n" ); document.write( "(0,0),(0,2),(3,0),(5,4) and (6,3) are not vertices of the
\n" ); document.write( "area that is enclose by y>=-x+3, y>=(-1/3)x+2, and y<=-3+9.
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\n" ); document.write( "Notice that two of the inequalities are above their boundary lines
\n" ); document.write( "and the 3rd is below it boundary line.
\n" ); document.write( "-------------
\n" ); document.write( "The vertices you want are (6,0),(9,0),(0,3),(0,9), and (3/2,3/2)
\n" ); document.write( "-------------
\n" ); document.write( "\"graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%28-1%2F3%29x%2B2%2C-x%2B3%2C-x%2B9%29\"
\n" ); document.write( "================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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