document.write( "Question 145873: JOE SPENT 1/3 OF HIS STUDY TIME DOING MATH HOMEWORK AND 2/7 PREPARING FOR A HISTORY EXAM. WHAT FRACTION OF HIS STUDY TIME REMAINS? \n" ); document.write( "
Algebra.Com's Answer #106464 by aswathytony(47)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the total study time of joe.\r \n" ); document.write( "\n" ); document.write( "then time used for doing math homework= 1/3 of x =1/3x\r \n" ); document.write( "\n" ); document.write( " time used for preparing history exam = 2/7 of x =2/7x\r \n" ); document.write( "\n" ); document.write( " let remaining time be 'y'.\r \n" ); document.write( "\n" ); document.write( "then, 1/3x+2/7x+ y =x\r \n" ); document.write( "\n" ); document.write( " y= x - [ 1/3x + 2/7x] \n" ); document.write( " = x - [ 7x + 6x/21] Taking LCM OF 3 & 7 , AND SIMPLIFYING \n" ); document.write( " = X- 13x/21 \n" ); document.write( " =21x -13x/21 taking LCM \n" ); document.write( " = 8x/21\r \n" ); document.write( "\n" ); document.write( "ie, fraction of remaining study time = 8/21 \n" ); document.write( " |