document.write( "Question 145856: In triangle ABC, the length of the altitude to side AB is 6 inches, and the measures of angles A and B are 45 and 60 degrees, respectively. What is the area of triangle ABC? express as a deimal to the nearest tenth.
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Algebra.Com's Answer #106459 by vleith(2983)\"\" \"About 
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Drop the altitude and find point D on AC. D cuts AC into two segments. \r
\n" ); document.write( "\n" ); document.write( "ABD has a side of 6 and A at 45. So AD is also 6.
\n" ); document.write( "BDC has a side 6 with C at 60. So DC is 6 / tan(60) = 3.46\r
\n" ); document.write( "\n" ); document.write( "AC = AD+DC = 6+3.46 = 9.46\r
\n" ); document.write( "\n" ); document.write( "area of ABC is bh/2 = 6*9.46/2 = 28.4 in^2
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