document.write( "Question 145857: Ann is 6 years older than Mary. She is also twice as old as Mary is when Ann was as old as Mary is now. How old is each girl? \n" ); document.write( "
Algebra.Com's Answer #106452 by 24HoursTutor.com(40)\"\" \"About 
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Assume Mary's age to be x
\n" ); document.write( "Which would mean Ann's age = 6 + x
\n" ); document.write( "Now, Ann was Mary's age 6 yrs ago which means : x-6
\n" ); document.write( "And now her age is twice the age of Mary 6 yrs ago : 2(x-6)\r
\n" ); document.write( "\n" ); document.write( "NOw, equating both the equations we get :
\n" ); document.write( "2(x-6) = 6 + x
\n" ); document.write( "2x-12 = 6 + x
\n" ); document.write( "2x - x = 6 + 12
\n" ); document.write( "x = 18\r
\n" ); document.write( "\n" ); document.write( "Hence, Mary's age is 18 yrs while Ann is 24 yrs old.\r
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