document.write( "Question 145857: Ann is 6 years older than Mary. She is also twice as old as Mary is when Ann was as old as Mary is now. How old is each girl? \n" ); document.write( "
Algebra.Com's Answer #106452 by 24HoursTutor.com(40)![]() ![]() ![]() You can put this solution on YOUR website! Assume Mary's age to be x \n" ); document.write( "Which would mean Ann's age = 6 + x \n" ); document.write( "Now, Ann was Mary's age 6 yrs ago which means : x-6 \n" ); document.write( "And now her age is twice the age of Mary 6 yrs ago : 2(x-6)\r \n" ); document.write( "\n" ); document.write( "NOw, equating both the equations we get : \n" ); document.write( "2(x-6) = 6 + x \n" ); document.write( "2x-12 = 6 + x \n" ); document.write( "2x - x = 6 + 12 \n" ); document.write( "x = 18\r \n" ); document.write( "\n" ); document.write( "Hence, Mary's age is 18 yrs while Ann is 24 yrs old.\r \n" ); document.write( "\n" ); document.write( "The above question is solved by one of the experts from 24HoursTutor.com \n" ); document.write( "We provide live 1:1 online homework help \n" ); document.write( "1. 24X7 tutors available \n" ); document.write( "2. Certified tutors \n" ); document.write( "3. Only for $9.99/hr \n" ); document.write( " |