document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145744>Question 145744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maria lights two candles of equal length at the same time.  One candle takes six hours to burn out and the other takes nine.  How much time will pass until the slower-burning candle is exactly twice as long as the faster-burning one? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106410 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=time __ 2[(6-x)/6]=(9-x)/9 __ multiplying by 9 __ 3(6-x)=9-x __ 18-3x=9-x\r<BR>\n" );
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document.write( "adding 3x-9 __ 9=2x __ 4.5=x </SPAN>\n" );
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