document.write( "Question 145773: You place $10,000 into two bank accounts. One of the accounts pays 2% and the other pays 3%. After one year you earned $250 in interest. How much money did you have in each account? \n" ); document.write( "
Algebra.Com's Answer #106402 by ankor@dixie-net.com(22740)\"\" \"About 
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You place $10,000 into two bank accounts. One of the accounts pays 2% and the other pays 3%. After one year you earned $250 in interest. How much money did you have in each account?
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\n" ); document.write( "Let x = amt invested at 3%
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\n" ); document.write( "It said the total invested is $10,000, therefore:
\n" ); document.write( "(10000-x) = amt invested at 2%
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\n" ); document.write( "Int at 3% + int at 2% = $250
\n" ); document.write( ".03x + .02(10000-x) = 250
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\n" ); document.write( ".03x + 200 - .02x = 250
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\n" ); document.write( ".03x - .02x = 250 - 200
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\n" ); document.write( ".01x = 50
\n" ); document.write( "x = \"50%2F.01\"
\n" ); document.write( "x = 5000 invested at 3%, then obviously, it's also 5000 invested at 2%
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\n" ); document.write( "Check solution
\n" ); document.write( ".03(5000) + .02(5000) =
\n" ); document.write( "150 + 100 = 250 \n" ); document.write( "
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