document.write( "Question 145761: The preimeter of a rectangle is 200 inches. The length exceeds the width by 46 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #106383 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! P= 2L + 2W ---------- eqn1 \n" ); document.write( "And L = W+46 \n" ); document.write( "So, \n" ); document.write( "200=2(W+46) + 2w \n" ); document.write( "200=2W+92+2W \n" ); document.write( "4W=200-92 \n" ); document.write( "W=108/4 \n" ); document.write( "W=27 inches \n" ); document.write( "For L = 27+46 = 73 inches \n" ); document.write( "In doubt? Go back eqn1, \n" ); document.write( "200= 2(73) + 2(27) \n" ); document.write( "200=146+54 \n" ); document.write( "200=200 \n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " \n" ); document.write( " |